Find the mode of the following distribution:
Class interval 10−1414−1818−2222−2626−3030−3434−3838−42Frequency8611202522104
As the class 26 – 30 has maximum frequency, so it is the modal class:
Therefore,
l=26, h=4, f=25 and f1=20 and f2=22
Mode
Mode = l+[h×(f−f1)/(2f−f1−f2)]
=26+[4×(25−20)(2×25−20−22)]
= 26 + (5/2) = (26+2.5) = 28.5
Hence, mode = 28.5