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Question

Find the mode of the following distribution:
Class interval 10141418182222262630303434383842Frequency8611202522104

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Solution

As the class 26 – 30 has maximum frequency, so it is the modal class:

Therefore,
l=26, h=4, f=25 and f1=20 and f2=22

Mode
Mode = l+[h×(f−f1)/(2f−f1−f2)]

=26+[4×(25−20)(2×25−20−22)]

= 26 + (5/2) = (26+2.5) = 28.5

Hence, mode = 28.5


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