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Question

Find the mode of the following frequency distribution:
Marks10202030304040505060Frequency1235452513

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Solution

As the class 30-40 has maximum frequency, so it is the modal class:

Using, Mode=l+(f1f02f1f0f2)h

where

l = lower limit of the modal class,

h = size of the class interval (assuming all class sizes to be equal),

f1 = frequency of the modal class,

f0 = frequency of the class preceding the modal class,

f2 = frequency of the class succeeding the modal class.

Mode=30+(45352453525)10

Mode=30+(1030)10

Mode=30+3.33

Mode=33.33


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