Find the mode of the following frequency distribution:
Marks10−2020−3030−4040−5050−60Frequency1235452513
As the class 30-40 has maximum frequency, so it is the modal class:
Using, Mode=l+(f1−f02f1−f0−f2)∗h
where
l = lower limit of the modal class,
h = size of the class interval (assuming all class sizes to be equal),
f1 = frequency of the modal class,
f0 = frequency of the class preceding the modal class,
f2 = frequency of the class succeeding the modal class.
Mode=30+(45−352∗45−35−25)∗10
⇒Mode=30+(1030)∗10
⇒Mode=30+3.33
⇒Mode=33.33