Find the mode of the given data- - Class-interval 0-20 20-40 40-60 60-80- Frequency 15 6 18 10- -

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Standard X

Mathematics

Finding Mode for Grouped Data When Class Intervals Are Given

Find the mode...

Question

Find the mode of the given data:

$\begin{matrix} C l a s s i n t e r v a l & 0 - 20 & 20 - 40 & 40 - 60 & 60 - 80 F r e q u e n c y & 15 & 6 & 18 & 10 \end{matrix}$

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Solution

As the class 40-60 has maximum frequency, so it is the modal class:

Therefore,
xk=40, h=20, fk=18 and fk−1=6 and fk+1=10

Mode = $(b) x_{k} + h . {\frac{(f_{k} - f_{k - 1})}{(2 f_{k} - f_{k - 1} - f_{k + 1})}}$

=40+[20×(18−6)/(2×18−6−10)]

= 40+(12)
= 52

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Find the mode of the given data: Class interval0−2020−4040−6060−80Frequency1561810

As the class 40-60 has maximum frequency, so it is the modal class: Therefore, xk=40, h=20, fk=18 and fk−1=6 and fk+1=10 Mode = (b) xk+h.{(fk−fk−1)(2fk−fk−1−fk+1)} =40+[20×(18−6)/(2×18−6−10)] = 40+(12) = 52

Find the mode of the given data:

$\begin{matrix} C l a s s i n t e r v a l & 0 - 20 & 20 - 40 & 40 - 60 & 60 - 80 F r e q u e n c y & 15 & 6 & 18 & 10 \end{matrix}$

As the class 40-60 has maximum frequency, so it is the modal class:

Therefore,
xk=40, h=20, fk=18 and fk−1=6 and fk+1=10

Mode = $(b) x_{k} + h . {\frac{(f_{k} - f_{k - 1})}{(2 f_{k} - f_{k - 1} - f_{k + 1})}}$

=40+[20×(18−6)/(2×18−6−10)]

= 40+(12)
= 52