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Byju's Answer
Standard XII
Mathematics
Modulus of a Complex Number
Find the modu...
Question
Find the modulus, argument and the principal argument of the complex numbers.
z
=
√
5
+
12
i
+
√
5
−
12
i
√
5
+
12
i
−
√
5
−
12
i
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Solution
z
=
√
5
+
12
i
+
√
5
−
12
i
√
5
+
12
i
−
√
5
−
12
i
=
(
√
5
+
12
i
+
√
5
−
12
i
)
(
√
5
+
12
i
+
√
5
−
12
i
)
(
√
5
+
12
i
−
√
5
−
12
i
)
(
√
5
+
12
i
+
√
5
−
12
i
)
=
(
√
5
+
12
i
+
√
5
−
12
i
)
2
(
√
5
+
12
i
)
2
.
(
√
5
−
12
i
)
2
=
(
5
+
12
i
)
+
(
5
−
12
i
)
−
2
√
5
+
12
i
√
5
−
12
i
5
+
12
i
−
5
+
12
i
=
10
−
2
×
13
25
=
−
16
25
−
0
i
∴
z
lies in x-axis.
Here
θ
=
tan
−
1
∣
∣
∣
0
−
16
/
25
∣
∣
∣
=
0
.
∴
a
r
g
(
x
)
=
2
π
−
θ
=
2
π
−
0
=
2
π
Hence, principal value of
a
r
g
(
z
)
=
−
θ
=
0.
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Similar questions
Q.
Find the modulus, argument and the principal argument of the complex number.
z
=
√
5
+
12
i
+
√
5
−
12
i
√
5
+
12
i
−
√
5
−
12
i
.
Q.
If
√
5
−
12
i
+
√
−
5
−
12
i
=
z
then principal value of arg z can be.
Q.
If
√
5
−
12
i
+
√
−
5
−
12
i
=
z
, then principal value of arg z can be
Q.
√
5
+
12
i
+
√
5
−
12
i
√
5
+
12
i
−
√
5
−
12
i
=
Q.
If
√
5
−
12
i
+
√
−
5
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i
=
z
, then principal value of
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can be
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