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Byju's Answer
Standard XII
Mathematics
Modulus of a Complex Number
Find the modu...
Question
Find the modulus of
1
−
i
√
5
−
i
√
3
.
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Solution
Now,
1
−
i
√
5
−
i
√
3
=
(
1
−
i
)
(
√
5
+
i
√
3
)
(
√
5
)
2
+
(
√
3
)
2
=
(
√
5
+
√
3
)
+
i
(
√
3
−
√
5
)
8
.
Now the modulus of the given complex number is
1
8
√
(
√
5
+
√
3
)
2
+
(
√
3
−
√
5
)
2
1
8
√
2
{
(
√
5
)
2
+
(
√
3
)
2
}
=
1
8
×
√
16
=
1
2
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Standard XII Mathematics
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