Find the molarity and molality of a 15% (w/w) H2SO4 solution.
(Density of the solution is 1.10 g/mL)
A
1.53 M, 1.64 m
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B
1.68 M, 1.68 m
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C
1.80 M 1.68 m
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D
1.68 M 1.80 m
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Solution
The correct option is D 1.68 M 1.80 m 15% (w/w) H2SO4⇒15gH2SO4 in 100 g of solution ⇒ 150 g H2SO4 in 1000 g solution Volumeofthesolution=Massdensity=10001.10=909mLMolarity=Number of moles of Solutevolume of solution in L ⇒150×100098×909=1.68MMass of solvent=1000−150=850gMolality=Number of moles of soluteMass of solvent in kg ⇒150×100098×850=1.80 m