MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Molarity

Find the mola...

Question

Find the molarity of a solution when $10 g$ of acetic acid is dissolved in water to make $800 m l$ of solution
$C H_{3} C O O H$ - Acetic Acid.

Open in App

Solution

Moles of acetic acid $= \frac{10}{60} = \frac{1}{6}$
$∴$ Molarity $= \frac{1 / 6}{800} \times 1000$
$= \frac{5}{24}$ M
$= 0.2083 M$

Suggest Corrections

thumbs-up

1

Similar questions

Q. When sodium acetate

(C H_{3} C O O N a)

is added to aqueous solution of acetic acid

(C H_{3} C O O H)

Q. How many moles of acetic acid and sodium acetate each should be dissolved to prepare one litre of

0.063

molar buffer solution of pH

4.5

K_{a}

{C H}_{3} C O O H = 1.8 \times 10^{- 5}

Q. The molar conductivity of acetic acid at infinite dilution is 390.7 and for 0.1 M acetic acid solution is 5.2 mho cm

^{2}

^{- 1}

. The degree of dissociation of 0.1 M

{CH}_{3} COOH

A buffer solution of pH = 5.15 is to be prepared from acetic acid (Ka =

$1.80x10^5$ ), sodium acetate and water. What must be the molar ratio of acetate ion to acetic acid in this solution to obtain this pH?

N a O H

was dissolved in 1 L of a solution containing one mole of acetic acid

C H_{3} C O O H

and one mole of sodium acetate

C H_{3} C O O N a

. Find the pH of the resulting solution.
The dissociation constant for

C H_{3} C O O H

1.8 \times 10^{- 5}

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Reactions in Solutions

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon