Find the moment of inertia of a uniform square plate of mass m and edge a about one of its diagonals.
Let small sectional area is at a distance x from xx` axis therefore mass at that small
sectionma2×a×dx
Therefore, moment of inertia about xx` axis
Ixx‘=2∫a20 ma2×(adx)×x2
=2×ma[x33]a20
=2×ma[a33×8]=ma212 Therefore, Izz=Ixx+Iyy
= 2×(ma212)=ma26
Izz=Ixx+Iyy
⇒ma26=2×Ixx (Ixx=Iyy)
⇒Ixx=ma212