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Question

Find the most general solution of 21+|cosx|+cos2x+|cosx|3+...=4

A
x=nπ±π9, nZ
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B
x=nπ±π6, nZ
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C
x=nπ±π12, nZ
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D
x=nπ±π3, nZ
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Solution

The correct option is D x=nπ±π3, nZ
We have 21+|cosx|+cos2x+|cosx|3+...=4
21+|cosx|+|cosx|2+|cosx|3+...=4
211|cosx|=22
1|cosx|=12
|cosx|=12 or cosx=±12
x=nπ±π3, nϵZ

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