wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate

(aman)mn×(anal)nl×(alam)lm


A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

a

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

1


(aman)mn×(anal)nl×(alam)lm

=(am+n)mn×(an+l)nl×(al+m)lm[Using kxky=kxy]

=(a)m2n2×(a)n2l2×(a)l2m2[Using (kx)y=kxy and Using (x+y)(xy)=x2y2]

Adding all the powers we get
=am2n2+n2l2+l2m2 (kx×ky=kx+y) =a0 =1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Indices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon