Question

Find the multiplicative inverse of
[3 MARKS]
$i)\frac{1}{4}+\frac{1}{6}$ $ii)0$

Answer 1

Concept : 1 Mark
Calculation : 2 Marks

i) We have, $\frac{1}{4}+\frac{1}{6}=\frac{3+2}{12}=\frac{5}{12}$

$\therefore {(\frac{1}{4}+\frac{1}{6})}^{-1}={\left(\frac{3+2}{12}\right)}^{-1}={\left(\frac{5}{12}\right)}^{-1}=\frac{12}{5}$

ii) There is no reciprocal of 0 as $\frac{1}{0}$ is not defined.