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Question

Find the n-factor for Zn in the following chemical changes.
(Zn+4HNO3(conc.)Zn(NO3)2+2NO2+2H2O)

A
3
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B
2
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C
1
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D
5
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Solution

The correct option is B 2
Steps for finding valency factor/n-factor:
1. Find the oxidation state (O.S.) of metal in reactant side.
2. Find the oxidation state of metal in product side.
3. Take the magnitude of difference of two oxidation state |O.S.ProductO.S.Reactant| for the valency factor
(ZnZn(NO3)2)
O.S. of Zn in product side
=x+2×(1)=0
x=+2
O.S. of Zn in reactant side
=2

valency factor=|O.S.ProductO.S.Reactant|
valency factor=|+20|
valency factor=2

Balanced chemical equation for the above change,
Zn+4HNO3(conc.)Zn(NO3)2+2H2O+2NO2
So, 1 mole of Zn loses 2 electrons.


for Zn=number of Zn atom×|O.S.ProductO.S.Reactant|=1×2
So, n factor =2

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