Find the n-factor in the following chemical change. KMnO4OH−−−−−→Mn6+
A
1
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B
4
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C
2
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D
3
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Solution
The correct option is A1 Steps for finding valency factor/n-factor:
1. Find the oxidation state (O.S.) of metal in reactant side.
2. Find the oxidation state of metal in product side.
3. Take the magnitude of difference of two oxidation state |O.S.Product−O.S.Reactant|×number of atom for the valency factor KMnO4OH−−−−−→Mn6+
O.S. of Mn in reactant side =+1+x+4×(−2)=0 x=+7
O.S. of Mn in product side=+6 valency factor=number of Mn atom×|O.S.Product−O.S.Reactant| valency factor=1×|+6−7| valency factor=1