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Question

Find the n-factor in the following chemical change.
KMnO4 OH− −−−−→Mn6+

A
1
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B
4
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C
2
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D
3
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Solution

The correct option is A 1
Steps for finding valency factor/n-factor:
1. Find the oxidation state (O.S.) of metal in reactant side.
2. Find the oxidation state of metal in product side.
3. Take the magnitude of difference of two oxidation state |O.S.ProductO.S.Reactant|×number of atom for the valency factor
KMnO4 OH −−−Mn6+
O.S. of Mn in reactant side
=+1+x+4×(2)=0
x=+7
O.S. of Mn in product side=+6
valency factor=number of Mn atom×|O.S.ProductO.S.Reactant|
valency factor=1×|+67|
valency factor=1

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