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Question

Find the n-factor of C2O24 in the following chemical changes.
C2O24CO2

A
0.0
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B
1
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C
3
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D
2
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Solution

The correct option is D 2
Steps for finding valency factor/n-factor:
1. Find the oxidation state (O.S.) of metal in reactant side.
2. Find the oxidation state of metal in product side.
3. Take the magnitude of difference of two oxidation state |O.S.ProductO.S.Reactant|×number of atom for the valency factor
C2O24CO2
O.S. of C in reactant side
=2x+4×(2)=2
x=+3
O.S. of C in product side
=x4=0
x=+4
valency factor=number of C atom×|O.S.ProductO.S.Reactant|
valency factor=2×|+34|
valency factor=2

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