Find the $n^{t h}$ term of the G.P. $1, 2, 4, 8, 16...$

2^{n + 1}

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2^{n - 1}

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2^{2 n + 1}

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2^{n}

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Solution

The correct option is B $2^{n - 1}$
Given series is $1, 2, 4, 8, 16, . . . .$
We know the formula for finding the $n^{t h}$ term as
$t_{n} = a r^{n - 1}$
Here $a = 1, r = 2$
So, $t_{n} = 2^{n - 1}$
Therefore, $n^{t h}$ term is $2^{n - 1}$ .

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