Find the nth term of the sequence m−1,m−3,m−5,.....
A
m−n+1
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B
m+2n+1
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C
m−2n+1
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D
m−2n
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Solution
The correct option is Cm−2n+1 Clearly, the given sequence is an AP with first term a=m−1 and common difference d=(m−3)−(m−1)=−2. ∴ nth term an=a+(n−1)d ⇒an=(m−1)+(n−1)×−2 =m−1−2n+2 =m−2n+1