Find the nth term of the series 3.4.7 + 4.5.9 + 5.6.11 + -------------
(n+2) (n+3) (2n + 5)
We see that each terms having the multiplication of 3 different Arithmetic progressions.
So,nth term of series is multiplication of nth terms of different APs.
nthTerm is tn = (n + 2) (n + 3) (2n + 5)