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Question

Find the nth term of the series 3.4.7 + 4.5.9 + 5.6.11 + -------------


A

(2n + 1) (2n + 2) (3n + 1)

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B

(n+2) (n+3) (n + 5)

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C

(n+2) (n+3) (2n + 5)

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D

(2n +1) (n + 3) (3n + 5)

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Solution

The correct option is C

(n+2) (n+3) (2n + 5)


We see that each terms having the multiplication of 3 different Arithmetic progressions.

So,nth term of series is multiplication of nth terms of different APs.

nthTerm is tn = (n + 2) (n + 3) (2n + 5)


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