Find the natural frequency of oscillation of the system as shown in figure. Pulleys are massless and frictionless. Spring and string are also massless. (Take π2=10)
With careful
analysis we can see that if mass m falls down by x distance,
the spring extends by 4x;
∴T4=k(4x)
T=(16k)x
where T is the restoring
force on mass m
∴f=12π√16km
⇒f=2π√km=2π×51=π2π=πHz