The correct option is A 70th maxima
The optical path difference (Δx) between the waves at P is given by
Δx=S2P−S1P=y1dD1+y1dD1
Δx=(1)(10)103+(5)(10)2×103
Therefore, Δx=0.035mm
Also, Δx=nλ=0.035mm
⟹n=0.035×10−35000×10−10=70
Hence a maxima of 70th order is obtained at P.