Find the nature of image when an object is placed at $2 f$ from the pole of a convex mirror of focal length $f$

Real, inverted and of same size

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Virtual, erect and of

\frac{1}{3}

times

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Virtual, erect and

3

times

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Real, inverted and

\frac{1}{3}

times

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Solution

The correct option is D Virtual, erect and of $\frac{1}{3}$ times
U=-2f

V=?

1/u+1/v=1/f

1/-2f + 1/v = 1 /f

1/v= 1/f + 1/2f

V = 2f/3

Now, m=-v/u

=-2f/3*-2f

=1/3
Virtual & erect

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Q. A student performs an experiment to estimate the focal length of a convex lens by obtaining the image of a distant window on a white screen. The image formed on the white screen is :
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Q. A teacher gives a convex lens and a concave mirror of focal length of about 20 cm each to his student and ask him to find their focal lengths by obtaining the image of a distant object. The student uses a distant tree as the object and obtains its sharp image, one by one, on a screen. The distance d₁ and d₂ between the lens/mirror and the screen in the two cases and the nature of their respective sharp images are likely to be:
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(2) (20 cm, 40 cm) and (inverted, erect)
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When an object is kept at any distance in front of a concave lens, the image formed is always : (a) virtual, erect and magnified (b) virtual, inverted and diminished. (c) virtual, erect and diminished (d) virtual, erect and same size as object

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Find the nature of image when an object is placed at 2f from the pole of a convex mirror of focal length f

The correct option is D Virtual, erect and of 13 timesU=-2f V=? 1/u+1/v=1/f 1/-2f + 1/v = 1 /f 1/v= 1/f + 1/2f V = 2f/3 Now, m=-v/u =-2f/3*-2f =1/3Virtual & erect

Find the nature of image when an object is placed at $2 f$ from the pole of a convex mirror of focal length $f$

The correct option is D Virtual, erect and of $\frac{1}{3}$ times
U=-2f

V=?

1/u+1/v=1/f

1/-2f + 1/v = 1 /f

1/v= 1/f + 1/2f

V = 2f/3

Now, m=-v/u

=-2f/3*-2f

=1/3
Virtual & erect