Question

Find the nature of roots of quadratic equation.
$2\sqrt{2}{x}^2+\sqrt{15}x+\sqrt{2}=0$

• A. No real solution
  
• B. $x=\sqrt{\frac{2}{3}}\pm \frac{41}{\sqrt{3}}i$
• C. Cannot be determined
  
• D. None of these
  

Answer 1

The correct option is A No real solution

$2\sqrt{2}{x}^2+\sqrt{15}x+\sqrt{2}=0$

Comparing with

$a{x}^2+bx+c=0$

Hence
$a=2\sqrt{2}$, $b=\sqrt{15}$, $c=\sqrt{2}$
Now, for discriminant:
$D=b^2-4ac$
$D=15-4\left(4\right)$
$D=15-16$
$D=-1<0$

Hence, no real solution.