Question

Find the nature of roots of the quadratic equation $4x^2-12x-9=0$

Answer 1

Here a=4,b=-12 and c=-9

$D=\sqrt{b^2-4ac}$

$D=\sqrt{(-12{)}^2-4(4\left)\right(-9)}$

$D=144+144=288$

Since,D>0 the roots are real and unequal.