Question

Find the nature of roots of the quadratic equation $y^2-7y+2=0$.

Answer 1

Given: a quadratic equation.

$y^2-7y+2=0$

which is of the form $a{x}^2+bx+c=0$

$\therefore a=1,b=-7,c=2.$

now, discriminant, $D=b^2-4ac$

$=(-7{)}^2-4(1\left)\right(2)$

= 49-8

= 41 > 0

Since D > 0, the two roots are real and distinct.