Find the nature of the roots and hance solve $a^{2} + 8 a + 16 = 0$

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Solution

The correct option is A

Given: $a^{2} + 8 a + 16 = 0$

$b^{2} - 4 a c = 64 - 4 (1) (16) = 0$

Since Discriminant is 0, the roots are real and equal.

$\Rightarrow$ $a^{2} + 8 a + 16 = 0$

$\Rightarrow$ $(a + 4)^{2} = 0$

$\Rightarrow$ $(a + 4) (a + 4) = 0$

$\Rightarrow$ $a = - 4, - 4$

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Find the nature of the roots and hance solve a2+8a+16=0

The correct option is A Given: a2+8a+16=0 b2−4ac=64−4(1)(16)=0 Since Discriminant is 0, the roots are real and equal. ⇒ a2+8a+16=0 ⇒ (a+4)2=0 ⇒ (a+4)(a+4)=0 ⇒ a=−4,−4

Find the nature of the roots and hance solve $a^{2} + 8 a + 16 = 0$

The correct option is A

Given: $a^{2} + 8 a + 16 = 0$

$b^{2} - 4 a c = 64 - 4 (1) (16) = 0$

Since Discriminant is 0, the roots are real and equal.

$\Rightarrow$ $a^{2} + 8 a + 16 = 0$

$\Rightarrow$ $(a + 4)^{2} = 0$

$\Rightarrow$ $(a + 4) (a + 4) = 0$

$\Rightarrow$ $a = - 4, - 4$