Find the nature of the roots of the equation $x^{2} - 4 x + 4 = 0$

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Solution

Here $a = 1, b = - 4, c = 4$

$Δ = b^{2} - 4 a c = {(- 4)}^{2} - 4 \times 1 \times 4 = 16 - 16 = 0$

$∴$ the roots are real and equal.

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Find the roots of quadratic equation x² - 4x + 4 = 0 using the quadratic formula.

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