Question

Find the nature of the roots of the following quadratic equations. If the real roots exist find them:
$2x^2-6x+3=0$

Answer 1

Consider the given equation.

$2x^2-6x+3=0$

$D=(-6{)}^2-4\times 2\times 3$

$D=36-24=12>0$

So, the roots are real and unequal.

Hence, this is the answer.