Question

Find the nature of the roots of the following quadratic equations. If the real roots exist find them:
$3x^2-4\sqrt{3}x+4=0$

Answer 1

Consider the given equation.

$3x^2-4\sqrt{3}x+4=0$

$D=(-4\sqrt{3}{)}^2-4\times 3\times 4$

$D=48-48=0$

So, the roots are real and equal.

Hence, this is the answer.