Find the nature of the roots of the following:
$x^{2} + x + 1 = 0$

Open in App

Solution

$x^{2} + x + 1 = 0$
In $a x^{2} + b x + c = 0$ form, $a = 1, b = 1, c = 1$
Discriminant $b^{2} - 4 a c = - 3$ , which is $< 0$
Hence, the root are complex.

Suggest Corrections

Similar questions

x^{2} + 2 x - 1 = 0

x^{2} - 2 x - 1 = 0

3 x^{2} + 7 x + 2 = 0

{(x + 3)}^{2} + 4 x + 7 = 0

2 x^{2} - 8 x + 34 = 0

x^{2} + 2 \sqrt{3 x} - 1 = 0

x^{2} - x - 3 = 0

6 x^{2} - 13 x + 6 = 0

\sqrt{6} x^{2} - 5 x + \sqrt{6} = 0

24 x^{2} - 17 x + 3 = 0

x^{2} + 2 x + 4 = 0

x^{2} + x + 1 = 0

x^{2} - 3 \sqrt{3} x - 30 = 0

Join BYJU'S Learning Program