MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nature of Roots

Find the natu...

Question

Find the nature of the roots of the quardtic equation $2 x^{2} - 6 x + 3 = 0$ . If the real root exit, find them.

Open in App

Solution

$2 x^{2} - 6 x + 3 = 0$

$D = b^{2} - 4 a c$

$D = (- 6)^{2} - 4 (2) (3)$

$D = 36 - 24 = 12$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Find the nature of the roots of the following quadratic equation. If the real roots exist, find them;

2 x^{2} - 6 x + 3 = 0

Q. Find the nature of the roots of the following quadratic equations. If the real roots exist find them:

2 x^{2} - 6 x + 3 = 0

Q. Find the nature of the roots of the following quadratic equations . If the real roots exit. find them:

2 x^{2} - 3 x + 5 = 0

3 x^{2} - \sqrt[4]{3} x + 4 = 0

Q. Question 1 (iii)
Find the nature of the roots of the following quadratic equations. If the real roots exist, find them;

(i i i) 2 x^{2} - 6 x + 3 = 0

Q. Find the nature of the roots of the following quadratic equation. If roots are real, find them

2 x^{2} - 9 x + 9 = 0

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Nature of Roots

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Nature of Roots

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon