Question

Find the nearest integer to the square root of $728.$

Answer 1

We know, ${26}^2=676$ and ${27}^2=729$
Also we have, $676<728<729$
$⟹{26}^2<728<{27}^2$

Difference of $676$ and $728$ is $52$ whereas difference of $728$ and $729$ is $1$.
So, the square root of $728$ is nearest to $27$.

Hence, the answer is $27$.