Find the nearest length of the diagonal of a rectangle that is 8 cm long and 5 cm wide.

9.1 cm

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9.2 cm

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9.3 cm

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9.4 cm

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Solution

The correct option is D 9.4 cm

So, $x^{2} = (5)^{2} + (8)^{2}$
$= 25 + 64$
$= 89$
$x = \sqrt{89} c m$
Thus, x = 9.4 cm

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