Question

Find the net resistance across $A$ and $B$

Answer 1

In the given circuit A And B are in parallel connection

$\frac{1}{R_{AB}}=\frac{1}{R_A}+\frac{1}{R_B}=\frac{9}{6}=\frac{3}{2}$

similarly D and E are in parallel combination

$\frac{1}{R_{DE}}=\frac{1}{R_D}+\frac{1}{R_E}=\frac{9}{6}=\frac{3}{2}$

Now Resistor C is in series connection with both AB and DE

Net resistance $R_{net}=\frac{3}{2}+\frac{3}{2}+3=6\omega$