Find the neutron-proton ratio in the daughter element when one - particle is emitted by 92 238 U-

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Standard IX

Chemistry

Properties of Alpha, Beta and Gamma Radiations

Find the neut...

Question

Find the neutron-proton ratio in the daughter element when one $α -$ particle is emitted by $_{92}^{238} U$ :

146 / 92

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144 / 92

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146 / 90

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144 / 90

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Solution

The correct option is A $144 / 90$
$_{92}^{238} U ⟶_{90}^{234} T h +_{2}^{4} H e$

$∵$ Number of protons in daughter element $= 90$

$∵$ Number of neutrons in daughter element
$= 234 - 90 = 144$

$∴ \frac{n}{p} = \frac{144}{90}$

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23892 U (I I I B)

changes to

28490 T h

by emission of

α

-particle. Daughter element will be in:

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Find the neutron-proton ratio in the daughter element when one α− particle is emitted by 23892U:

The correct option is A 144/9023892U⟶23490Th+42He∵ Number of protons in daughter element=90∵ Number of neutrons in daughter element=234−90=144∴np=14490

Find the neutron-proton ratio in the daughter element when one $α -$ particle is emitted by $_{92}^{238} U$ :

The correct option is A $144 / 90$
$_{92}^{238} U ⟶_{90}^{234} T h +_{2}^{4} H e$

$∵$ Number of protons in daughter element $= 90$

$∵$ Number of neutrons in daughter element
$= 234 - 90 = 144$

$∴ \frac{n}{p} = \frac{144}{90}$