Find the next number in the following sequence: 42.00, 39.50, 37.00, 34.50, ...
32.00
The given sequence is: 42.00, 39.50, 37.00, 34.50, ...
Note that the difference between the consecutive terms in the above sequence is -2.50
Hence the given sequence forms an AP whose first term (a) is 42.00 and the common difference (d) is -2.50
Therefore the 5th term of the above sequence is,
a5 = 42.00 + (5-1)(-2.50) (∵ an = a + (n-1)d)
⟹ a5 = 32.00