Find the next term of the sequence:
$2, 5, 8, 11, . . . . . . . . . .$

14

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15

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16

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18

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Solution

The correct option is B $14$
Given sequence is $2, 5, 8, 11, . . . . .$
Here $t_{1} = 2, t_{2} = 5, t_{3} = 8, t_{4} = 11$
$t_{2} = 2 + 1 \times 3 = 5$
$t_{3} = 2 + 2 \times 3 = 8$
$t_{4} = 2 + 3 \times 3 = 11$
Clearly it is an AP with first term $a = 2$ and common difference $d = 3$
$t_{n} = a + (n - 1) d$
$∴ t_{5} = 2 + 4 \times 3 = 14$
Hence, the answer is $14$ .

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