Find the nitrogen percentage in $[C O (N H_{2})_{2}]$ :

23

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28

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46.67

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25

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Solution

The correct option is C $46.67$
Total molecular weight of compound $[C O (N H_{2})_{2}]$ :
$= 12 + 16 + 2 (14 + 2) = 60$
Weight of $2 m o l e s$ of $N$ in molecule $= 2 \times 14 = 28$
Nitrogen content of molecule $= \frac{28}{60} \times 100 = 46.67 %$

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