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Stoichiometry

Find the norm...

Question

Find the normality of oxalic and solution containing $63 g$ of crystalline oxalic acid in $500 m l$ of solution.

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Solution

Equivalent weght of oxalic acid is 63 grams
$N o r m a l i t y = \frac{W e i g h t \times 1000}{e q . w e i g h t \times v o l u m e}$
$N o r m a l i t y = \frac{63 \times 1000}{63 \times 500} = 2 N$

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