Question

Find the nth term of the A.P. 's :
$\frac{1}{2},\frac{3}{2},\frac{5}{2},\frac{7}{2},\frac{9}{2},....$

Answer 1

$a=\frac{1}{2}$

$\Rightarrow d=1$

$T_n=a+(n-1)d$

$=\frac{1}{2}+n-1=n-\frac{1}{2}$