Find the nth term of the H.P. $1, 2, 3, 4, 5...$

\frac{1}{1 + (n - 1)}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{1 - (n - 1)}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{1 + (n - 2)}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 + (n - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{1}{1 + (n - 1)}$
Given series is $1, 2, 3, 4, 5, . . .$
Here first term $= a = 1$ and common difference $= d = 1$
Therefore, HP $= \frac{1}{a + (n - 1) d}$
$= \frac{1}{1 + (n - 1) 1}$
$= \frac{1}{1 + (n - 1)}$

Suggest Corrections

Similar questions

Find the nth term of the following series $2 + 5 x + 8 x^{2} + 11 x^{3} + . . . . . .$

Q. If sum of the n terms of a sequence is (n-1)2, find the nth term of the sequence.

Find the sum of the series whose nth term is :

(i) $2 n^{3} + 3 n^{3 - 1}$

(ii) $n^{3} - 3^{n}$

(iii) $n^{(} n + 1) (n + 4)$

(iv) $(2 n - 1)^{2}$

The Fibonacci sequence is defined by $a_{1} = 1, a_{2}, a_{n} = a_{n - 1} + a_{n - 2}$ for n > 2. Find $\frac{a_{n + 1}}{a_{n}}$ for n = 1, 2, 3, 4, 5.

The Fibonacci sequence is defined by $1 = a_{1} = a_{2}$ and $a_{n} = a_{n - 1} + a_{n - 2}, n > 2$
Find $\frac{a_{n + 1}}{a_{n}}, f o r n = 1, 2, 3, 4, 5$

Join BYJU'S Learning Program

Find the nth term of the H.P. 1,2,3,4,5...

The correct option is A 11+(n−1)Given series is 1,2,3,4,5,...Here first term =a=1 and common difference =d=1Therefore, HP =1a+(n−1)d=11+(n−1)1=11+(n−1)

Find the nth term of the H.P. $1, 2, 3, 4, 5...$

The correct option is A $\frac{1}{1 + (n - 1)}$
Given series is $1, 2, 3, 4, 5, . . .$
Here first term $= a = 1$ and common difference $= d = 1$
Therefore, HP $= \frac{1}{a + (n - 1) d}$
$= \frac{1}{1 + (n - 1) 1}$
$= \frac{1}{1 + (n - 1)}$