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Question

Find the number in place of P in the following number series:

188186P174158126
Now, find the value of the expression P13.

A
14.03
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B
14.10
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C
13.00
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D
13.67
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Solution

The correct option is A 13.00
Series188186P174158126
Common differences are,
186188=2,P186,174P,158174=16 and P186,174P,158174=16
differences are in increasing order with negative sign
so differences are 21,P186,P174,24,26
So,P174=23orP186=22P=174+8orP=1864=182P=182
Value of P13=18213=169=13
Answer (C).

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