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Question

Find the number of a for which given equation have equal rootsx2+3x(a2+a2)=0

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Solution

x2+3x(c2+a2)=0
For roots to be equal,
b2+4ac=0
9+4(a2+a2)=0
a2+a2=94
a2+a+14=0
4a2+4a+1=0
4a2+2a+2a+1=0
2a(2a+1)+1(2a+1)=0
a=12

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