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Question

Find the number of all the integral solutions of the inequality (x2+2)(x216)(x4+2)(x29)0

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is D 4
(x2+2)x216(x4+2)(x29)0x2+2>0,x216>0,x4+2>01x2901(x3)(x+3)0x{2,1,0,1,2}x216>0x2>16
x29<0 and x216>0 cant be possible at a time.
Given equation is valid only at x216=0
x=±4

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