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Question

Find the number of aluminium ions present in 0.051g of aluminium oxide(Al2O3).
(Atomic mass : Al = 27 amu ; O = 16 amu)

A
5×1020
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B
10×1020
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C
6×1020
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D
8×1020
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Solution

The correct option is B 6×1020
Given mass of aluminium oxide = 0.051 g
molar mass of Al2O3 = 102
so, number of moles of Al2O3 = 0.051102 = 0.0005 moles
we have
Al2O32Al3+
1 mole of Al2O3 gives 2 moles of Al3+ ions,
so 0.0005 moles of Al2O3 gives Al3+ ions = 0.0005×2=0.001moles

1 mole of Al3+ ions have number of Al3+ ions = 6.023×1023

so, 0.001 moles of Al3+ ions contains number of Al3+ ions = 6.023×1023×0.001=6×1020ions

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