Find the number of amphoteric hydroxide(s) from the following :
$B e (O H)_{2}, M g (O H)_{2}, A l (O H)_{2}, L i O H, B (O H)_{3}, Z n (O H)_{2}$

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Solution

The number of amphoteric hydroxides is 3.
$B e (O H)_{2}, Z n (O H)_{2}$ and $A l (O H)_{2}$ are amphoteric in nature. They react with acids as well as bases.
$L i O H$ and $M g (O H)_{2}$ are basic.
$B (O H)_{3}$ is acidic in nature.

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Similar questions

B e (O H)_{2}, M g (O H)_{2}, A l (O H)_{3}, L i O H, B (O H)_{3},

B e (O H)_{2}, M g (O H)_{2}, A l (O H)_{3}

B (O H)_{3}

B (O H)_{3}, M g (O H)_{2}, S i (O H)_{4}, S O_{2} (O H)_{2}, B a (O H)_{2}

H_{2} O ?

(1) B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

(2) B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

(3) L i O H < N a O H < K O H < R b O H

(4) L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

H_{2} O

B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

L i O H < N a O H < K O H < R b O H

L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

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