The number of ancestors are
2,4,8,16,
It is a G.P. since,
4/2= 2
8/4= 2
Common ratio = 2
First term = a = 2
& number of generations (n) = 10
We have to find the number of his ancestors during the ten
generations preceding his own,
i.e. S10
As r>1
Sum of n terms in GP = [a((r^n)) - 1]/(r-1)
i.e. Sn = a[r^n -1]/(r-1)
Putting values of a=2, r=2, & n=10
S10 = [2×((2^10)-1]/(2-1)
S10= 2×1023/1
S10 = 2046
Hence, the number of ancestors preceding the person is
2046.