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Question

Find the number of digits 1025th term of the sequence 1,2,2,4,4,4,4,8,8,8,8,8,8,8,8

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Solution

The 1st position in the sequence is 1 and occurs one time.
The 2nd position in the sequence is 2 and occur twice
The 4th position in the sequence is 4 and occurs four times
All the member in the sequence are power of 2
So, 1024th position in the sequence would be 1024 and would occur 1024 times
1025th term in the sequence would be 1024

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