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Byju's Answer
Standard IX
Mathematics
Laws of Exponents for Real Numbers
Find the numb...
Question
Find the number of digits in the numeral for
(
875
)
16
Open in App
Solution
875
=
25
×
35
=
5
2
×
5
×
7
=
5
3
×
7
(
875
)
16
=
(
5
3
×
7
)
16
=
(
5
3
)
16
×
7
16
=
5
48
×
7
16
Taking
l
o
g
10
l
o
g
(
875
)
16
=
l
o
g
10
5
48
+
l
o
g
10
7
16
∴
l
o
g
(
a
b
)
=
l
o
g
10
a
+
l
o
g
10
b
=
48
l
o
g
10
5
+
16
l
o
g
10
7
=
48
l
o
g
10
(
10
2
)
+
16
l
o
g
10
7
(
∵
l
o
g
10
10
=
1
)
=
48
[
1
−
l
o
g
2
]
+
16
l
o
g
7
=
16
[
3
(
1
−
0.3010
)
+
0.845
]
16
×
[
3
×
0.699
+
0.845
]
=
47.072
≃
48
digits.
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