Question

Find the number of digits in the square root of the number $4489$.

Answer 1

State the formula according to condition and compute the number of digits in square root of given number

Let, $n=$ the number of digits in the given number.

When $n$ is even, the number of digits in the square root is $\frac{n}{2}$.

When $n$ is odd, the number of digits in the square root is $\frac{n+1}{2}$.

Consider the number $4489$

There are four digits in $4489$. Here the number of digits is even. So,

$No.ofdigitsinsquareroot=\frac{n}{2}$

$$\begin{gathered} =\frac{4}{2} \\ =2 \end{gathered}$$

Hence, there are $2$ digits in the square root of $4489$.