Question

Find the number of electrons involved in the electro-deposition of 63.5 gram of copper from a solution of copper sulfate.

Answer 1

$Cu\to C{u}^{++}+2e^{-}$ i.e, to deposit 1 mole of Cu at cathode from $C{u}^{2+}S{O}_4^{2-}$ solution= 2mole pf electrons are required

To deposit $63.5g=\frac{63.5}{63.5}\times 2=2moles$

Thus total number of electrons required $2N_A$