Find the number of electrons lost or gained in the following reaction a MnOH2 - H2O2 - MnO2 - 2H2Ob AlCl3 - 3K - Al - 3KCl respectively-

A) Mn^2+→ Mn^4+ + 2e^ (Oxidation) 2e^ + H_2O_2 → 2H_2O (Reduction) number of electron lost/gain = 2 b) nbsp;nbsp; 3K → 3K^+ +3e^ (Oxidation) 3e^ + Al^3+→ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Valency and Oxidation State

Find the numb...

Question

Find the number of electrons lost or gained in the following reaction
a) $M n (O H)_{2} + H_{2} O_{2} \to M n O_{2} + 2 H_{2} O$
b) $A l C l_{3} + 3 K \to A l + 3 K C l$ respectively.

2, 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3, 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4, 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0, 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2, 3
a) $M n^{2 +} \to M n^{4 +} + 2 e^{-}$ (Oxidation)
$2 e^{-} + H_{2} O_{2} \to 2 H_{2} O$ (Reduction)
number of electron lost/gain = 2

b) $3 K \to 3 K^{+} + 3 e^{-}$ (Oxidation)
$3 e^{-} + A l^{3 +} \to A l$ (Reduction)
number of electron lost/gain = 3

Hence, the correct option is a

Suggest Corrections

Similar questions

Q. Find the number of electrons lost or gained in the following reaction
a)

M n (O H)_{2} + H_{2} O_{2} \to M n O_{2} + 2 H_{2} O

A l C l_{3} + 3 K \to A l + 3 K C l

respectively.

Q. Calculate the number of electrons lost or gained during the changes.

A l C l_{3} + 3 K \to A l + 3 K C l

Q. Match the reactions given in List I with the number of electrons lost or gained in List II

\begin{matrix} C o l u m n - I & C o l u m n - I I R e a c t i o n & N u m b e r o f e l e c t r o n s l o s t o r g a i n e d (P) & M n (O H)_{2} + H_{2} O_{2} \to M n O_{2} + 2 H_{2} O & (1) & 8 (Q) & A l C l_{3} + 3 K \to A l + 3 K C l & (2) & 2 (R) & 3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2} & (3) & 3 (S) & 3 H_{2} S + 2 H N O_{3} \to 3 S + 2 N O + 4 H_{2} O & (4) & 6 \end{matrix}

Q. Match the reactions given in List I with the number of electrons lost or gained in List II

\begin{matrix} C o l u m n - I & C o l u m n - I I R e a c t i o n & N u m b e r o f e l e c t r o n s l o s t o r g a i n e d (P) & M n (O H)_{2} + H_{2} O_{2} \to M n O_{2} + 2 H_{2} O & (1) & 8 (Q) & A l C l_{3} + 3 K \to A l + 3 K C l & (2) & 2 (R) & 3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2} & (3) & 3 (S) & 3 H_{2} S + 2 H N O_{3} \to 3 S + 2 N O + 4 H_{2} O & (4) & 6 \end{matrix}

A l C l_{3} + K \to A l + 3 K C l

If the number of electrons lost or gained during the changes is

x

. Then, the value of

x

is :

Join BYJU'S Learning Program

Explore more

Valency and Oxidation State

Standard XII Chemistry

Join BYJU'S Learning Program

Find the number of electrons lost or gained in the following reaction a) Mn(OH)2+H2O2→MnO2+2H2O b) AlCl3+3K→Al+3KCl respectively.

The correct option is A 2, 3a) Mn2+→Mn4++2e− (Oxidation) 2e−+H2O2→2H2O (Reduction) number of electron lost/gain = 2 b) 3K→3K++3e− (Oxidation) 3e−+Al3+→Al (Reduction) number of electron lost/gain = 3 Hence, the correct option is a

Find the number of electrons lost or gained in the following reaction
a) $M n (O H)_{2} + H_{2} O_{2} \to M n O_{2} + 2 H_{2} O$
b) $A l C l_{3} + 3 K \to A l + 3 K C l$ respectively.